![]() ![]() Uppermost disk(smallest one) of poleC is being moved to poleB.Then,uppermost disk(largest one) of poleA is being moved to poleC.Īgain,uppermost disk(smallest one) of poleB is being moved to poleA.Also uppermost disk(second smallest one) of poleB is being moved to poleC.įinally,all the disks is being moved to poleC. Now uppermost disk(second smallest one) of poleA is being moved to poleB. first pole is A,second pole is B and third pole is Cįirstly all the disks is in poleA and then the uppermost disk(smallest one) is being moved to poleC. My solution is a bit weak, but from playing around with it. Since this is a recursive approach so,it is quite difficult to understand this by just reading the algorithm so,let's take an example to have a better idea of the solution. where a to b indicates moving the top disk on peg a to peg b. The solution to this problem is required some moves to be repeated depending on whether n is even or odd and it is based on the below fact At any given time, there is only one legal move between any two pegs. At last, we will make another recursive call to transfer all the disks from auxiliary pole to destination pole with the help of source pole. Solution: If there are n discs in a Tower Of Hanoi puzzle, then the total number of moves required to solve the puzzle will be 2 n 1.If the number of disks in the source pole is left 1 then transfer it to destination pole.This will be handled through base case.First of all, we will make a recursive call to transfer all the disks from source pole to auxiliary pole with the help of destination pole except the last disk.A larger disk can't be placed on a smaller disk.A disk can only be moved if it is the uppermost disk in the pole.There are some rules which needs to be followed at the time of solving this puzzle. The objective of the puzzle is to move all the disks from one pole (source pole) to another pole (destination pole) with the help of the third pole (auxiliary pole). The puzzle begins with the disks stacked on. I guess it is not correct as the number of moves are not 2n - 1, for eg, for 3 disks to be moved, it has to generate 7 moves. The Tower of Hanoi (also called The problem of Benares Temple 1 or Tower of Brahma or Lucas' Tower 2 and sometimes pluralized as Towers, or simply pyramid puzzle 3) is a mathematical game or puzzle consisting of three rods and a number of disks of various diameters, which can slide onto any rod. The puzzle starts with the disk in ascending order of size in one pole, the smallest at the top. I have written the following code for Towers of Hanoi problem using non recursive approach. It consists of three poles and a number of disks of different sizes which can slide onto any poles. We will get started with Tower Of Hanoi Problem now. Time & Space Complexity of Iterative Approach.Iterative Implementation of Tower Of Hanoi.Time & Space Complexity Analysis of Tower Of Hanoi.Recursive Implementation of Tower Of Hanoi.It is used to demonstrate the simple rules to solve a problem and lead to exponential number of steps. Tower Of Hanoi (TOH) is a mathematical puzzle which can be easily solved by recursive algorithm. ![]()
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |